Officially: the winner of the Premier League’s Player of the Season award revealed


Manchester City midfielder Kevin De Bruyne

Manchester City midfielder Kevin De Bruyne won the Premier League

Player of the Year award for the 2019-2020 season on Sunday.

De Bruyne won the award based on a vote by EA Sports that specializes in ,

developing esports featuring fans, as well as leaders of the 20 Premier League clubs and a group of football professionals.

De Bruyne’s crowning

De Bruyne’s crowning comes hours after his team bid farewell to the Champions League, following a 1-3 defeat by Lyon in the quarter-final,

in which he scored his team’s only goal.

The midfielder led his team to finish second in the championship standings behind Liverpool after equaling the record for the number of decisive passes in one season,

recorded by the French former Arsenal player Thierry Henry (20 assists in the 2002-2003 season), in addition to 13 goals.


De Bruyne, 29, is the third Belgian player to be named the best player in the English championship after his former colleague Vincent Kompany (2011-2012) and the current Real Madrid player,

and former Chelsea, was convicted Hazar 2014-2015.

The Belgian beat Trent Alexander-Arnold, Jordan Henderson, Senegalese Sadio Mane (Liverpool),

striker Danny Ings (Southampton), goalkeeper Nick Pope (Burnley) and tournament scorer Jamie Vardy (23 goals with Leicester City),

who competed with him in the final shortlist.

Alexander-Arnold won the Best Young Player award, while his German coach Juergen Klopp won the best coach title after leading Liverpool to their first league title in 30 years,

and South Korean Son-Heung-min won the best goal award.

It is noteworthy that the prize last season went to the Dutch defender Vergil Van Dyck.

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